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Filename.replace(/^.*[\\\/]/, '') -: explain the expression

Pakhi
New Contributor III

‎04-11-2022 05:36 AM

Hi can anyone make me understand the below expression.

FileName.replace(/^.*[\/]/, ‘’)

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4 REPLIES 4

bojanvelevski
Valued Contributor

‎04-11-2022 05:46 AM

Hey @Pakhi,

This expression will replace the element that is matched by the regex (/^.*[/]/), with an empty string ''

Pakhi
New Contributor III
In response to bojanvelevski

‎05-09-2022 06:35 AM

Hey can you explain this regex please if you know

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bojanvelevski
Valued Contributor
In response to Pakhi

‎05-09-2022 06:42 AM

Sure.

  . - matches any character except a line break
  * - means 0 or more of the preceding token
  [ ] - means a character set
  \/ - is practically an escaped forward slash character - /

siwadon
Employee
Employee

‎05-09-2022 10:15 AM

Basically, the expression removes anything from the beginning of the string to the last forward slash or backslash. In other words, get only the filename from the input string.

See some examples in the screenshot below. The highlighted parts are matched with ^.*[\\\/] and will be removed.
regex_basename