Filename.replace(/^.*[\\\/]/, '') -: explain the expression

Pakhi · April 11, 2022, 12:36pm

Hi can anyone make me understand the below expression.

FileName.replace(/^.*[\/]/, ‘’)

bojanvelevski · April 11, 2022, 12:46pm

Hey @Pakhi,

This expression will replace the element that is matched by the regex (/^.*[/]/), with an empty string ''

Pakhi · May 9, 2022, 1:35pm

Hey can you explain this regex please if you know

bojanvelevski · May 9, 2022, 1:42pm

Sure.

  . - matches any character except a line break
  * - means 0 or more of the preceding token
  [ ] - means a character set
  \/ - is practically an escaped forward slash character - /

siwadon · May 9, 2022, 5:15pm

Basically, the expression removes anything from the beginning of the string to the last forward slash or backslash. In other words, get only the filename from the input string.

See some examples in the screenshot below. The highlighted parts are matched with ^.*[\\\/] and will be removed.