Like how to get AddressNO group by the same IDs like below?
1 ACCEPTED SOLUTION
Oh, sorry for the misunderstanding. You want to generate the AddressNO based on the number of elements for each ID?
Youโll have to modify the sort and group by to do so by ID. Then afterwards youโll need a Mapper snap using the map expression.
$group.map((e, index) => e.extend({'AddressNO': index + 1}))
For each element that was group, this will extend it with the index in the group array.
Finally now that the elements have an AddressNO you can split everything back out using the JSONSplitter snap.
Iโve updated the pipeline so you can try it out yourself.
groupby-example_2018_10_26.slp (8.0 KB)
If I understand your question, youโre trying to group your data set by the AddressNO field. That is, the expected output would have all rows with AddressNO equal to one grouped, and all AddressNO equal to two grouped, etc.
If thatโs the case, then youโll need to sort on AddressNO and then use a group by field snap.
Here is the pipeline in my example if you want to upload it and try it out.
groupby-example_2018_10_25.slp (5.1 KB)
Oh, sorry for the misunderstanding. You want to generate the AddressNO based on the number of elements for each ID?
Youโll have to modify the sort and group by to do so by ID. Then afterwards youโll need a Mapper snap using the map expression.
$group.map((e, index) => e.extend({'AddressNO': index + 1}))
For each element that was group, this will extend it with the index in the group array.
Finally now that the elements have an AddressNO you can split everything back out using the JSONSplitter snap.
Iโve updated the pipeline so you can try it out yourself.
groupby-example_2018_10_26.slp (8.0 KB)
