Forum Discussion
5 Replies
- delContributor III
There’s got to be an easier way, but I succeeded with a Mapper containing the following expression and then a Splitter following the Mapper.
$Errors.replace(/\d+. /g,“|”).split(“|”).map(x => {“Name”:$Name,“FMNO”:$FMNO,“Phone #1”:$[‘Phone #1’],“Phone #2”:$[‘Phone #2’],“Email”:$Email,“Error”:x}).filter((v,k)=>v.Error!=“”)
- delContributor III
LOL, I challenged myself to make it better. It’s not prettier, but you’re not stuck to hard-coding column names.
$Errors.replace(/ *\d+. /g,“|”).split(“|”).map(x => $.mapValues((v1,k1)=>k1 == “Errors” ? x : v1).mapKeys((v2,k2)=>k2 == “Errors” ? “Error” : k2)).splice(1)
Surely, someone can improve on this even…
- walkerline117Contributor
Thanks so much, it really helps.
The only thing is that the result comes into different groups by ppl name.
How to flat the result so everything goes into one structure(no group)Thanks
- nganapathirajuFormer Employee
Do something like the below steps.
- In the Mapper - Errors.split(‘.’) - but it will not split when you have only one error. You need to come up with some logic there.
- add a JSON splitter and
- split in on Errors
- use scalar parents checkbox or add the path you want to. The former should work for this.