Hi
I have a use case where I am looking forward to access methods of one library(expression file) from another library (expression file 2).
Is their a way to achieve this?
Thanks @tstack
This helped me a lot.
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You should be able to reference the other library through the lib variable. Is that not working?
For example, if you this as the library helper.expr:
{
chefify: x => x + ' bork! bork! bork!'
}
You should be able to reference it from another library, like so:
{
msg: () => lib.helper.chefify('Hello, World!')
}
Note that if the references are not in functions, but directly in the top-level expression, youâll need to ensure the libraries are listed in the right order in the pipeline properties.
I found a better way to achieve what i was look for.
But thanks for highlighting this.@tstack
I have a use case where a child pipeline has multiple expr files.
I want to pass a value to the child pipeline using which my chiled pipeline would choose one of the expression library.
is there a way to do it ?
In the child pipeline properties, add a parameter that youâll use to specify the library to load. Then, in the âExpression Librariesâ section, add a path that uses the parameter you just created. Youâll probably also want to set the name of the imported library using the âAsâ column. In the screenshot below, the parameter is config and defaults to the library file dev.expr and the library can be referenced via lib.conf in expressions:
In the parent pipeline, youâll pass the config parameter with the library paths that you want. In the screenshot below, there are two documents entering the PipeExec with âdev.exprâ and âprod.exprâ as the paths. So, the child will execute first with the âdevâ library and then with the âprodâ library.
Is there a way to declare methods with global scope in expression library.
Is nesting multiple libraries together a good preactice ?
Do you mean without the lib.libname prefix? No, libraries are always imported under the lib object.
Iâm not sure what you mean by this, can you give an example?
