I have strings that are storing a two digit number (i.e. 00, 01, 02, etc) but I need to add another leading zero (i.e. 000, 001, 002). I don’t want to simply concatenate a 0 on the front in case I have values that end up being three digits.
Thank you @tstack! That worked!
(“0” + $value).slice(-3)
.slice(-3) will take the last 3 characters in the string
This worked well. I was padding a string with spaces. Beware that when I validated the pipeline the string in the preview data was not displayed with the padding, but the string was actually padded as expected.
Here is an alternative solution if you need something that works for any value.
Example with padding with six zeros:
I have chosen to store the padding value in pipeline params as pad6 = "000000"
$value.toString().length < 6 ? _pad6.substring(0, _pad6.length - $value.toString().length) + $value.toString() : $value.toString()
Thanks @tstack
So this would be an alternative solution:
$value.toString().length < 6 ? '0'.repeat(6 - $value.toString().length) + $value : $value
It feels a more sleek than my existing padding 🙂
$value = “01”.
I’ve tried $value.sprintf(“%03d”, “0”) and several other similar things but it doesn’t seem to work.
It looks like the format and the value to format are switched around. The sprintf() method is to be called on the format string, like so:
"%03d".sprintf(parseInt($value))
Note that the value passed in needs to be a number and not a string, which is why I used parseInt().
Thank you @tstack! That worked!
