Forum Discussion
Hi @Pakhi,
Try this.
sl.range(6).map(x => "0123456789ABCDEF"[Math.round(Math.random()*15)]).join('')
Regards,
Viktor
Thanks its working!
Can you please explain this expression , actually how its working internally.
sl.range(6)
- Generates me a list with number of elements.
Inside the parameter is specified how many elements to have the list.
Ex.[0,1,2,3,4,5]
After that with the
map()
function I iterate through that list.
And while iterating, for each element is generated a random number between 0 and 15.Random number is generated with
Math.random()
andMath.round()
functions.-
Math.random()
- Generates a decimal number between 0 and 1. -
Math.random()*15
- Generated number is multiplied by the number of characters in the string. -
Math.round(Math.random()*15)
- Decimal number is rounded to the nearest whole number.
Ex.3.656
- will be rounded to4
.
Generated random number I use it as an index from which I get character from the string.
Ex."0123456789ABCDEF"[4] = "3"
(returns the 4th index from the string).Now if we look at the preview of this expression, result will be list of strings.
Ex.["3", "8", "A", "1", "C", "D"]
At the end the list is joined with
join()
function. This function is used for transforming list into string. Parameter inside join function (''
) means that it will join the elements together without nothing between the elements.Result at the end will be this:
"38A1CD"
Hope this will help understand the expression 🙂
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