Hey @darshthakkar,
I suppose you can remove the curly brackets from your final string, but if you want to go and make this solution totally dynamic, than I suggest to remove the brackets on an object level with the following expression:
$group.map(x=>x.toString().substring(1,x.toString().length-1)).toString()
What we’re doing here is first we’re mapping/iterating through the array and turning every object in it into a string:
[{
"name": "John",
"age": 33
},
{
"name": "Jack",
"age": 23
},
{
"name": "Jill",
"age": 43
}]
will become:
[
"{name=John, age=33}"
"{name=Jack, age=23}"
"{name=Jill, age=43}"
]
In the same iteration we’re removing the first and last character which are the object curly brackets. The rest is clear, just concatenate the strings in the array:
[
"name=John, age=33"
"name=Jack, age=23"
"name=Jill, age=43"
]
End result:
name=John, age=33,name=Jack, age=23,name=Jill, age=43
With this we’re excluding any possibility of removing a curly brackets which are in the values of the JSON objects and should not be excluded.
Sample:
[
{
"name": "John{test}",
"age": 33
},
{
"name": "Jack{test}",
"age": 23
},
{
"name": "Jill{test}",
"age": 43
}
]
Result while replacing curly brackets on final string:
name=Johntest, age=33,name=Jacktest, age=23,name=Jilltest, age=43
Result while removing curly brackets on object level with mapping:
name=John{test}, age=33,name=Jack{test}, age=23,name=Jill{test}, age=43
Regards,
Bojan
