Zip File Read – pass file name to text field
Hello, we have a data coming in a zip file. One of the requirements is to read file name and send it to a text field so it can be loaded in to one of the columns in Oracle table.
For example:
Fil...
Forum Discussion
It looks like the value of content-location coming out of the Mapper is the file name minus the path.
If you were to put a Copy after the Mapper, followed by a Mapper to only use content-location (remap to FileName), then join it back at the JSON Splitter.
Thank you, Diane. Unfortunetly, FileName is not coming through after Json Parser and therefore, there is no way to get to it in JSON Splitter.
ZipFile Read produces following output:
JSON Parser follows directly after ZipFile Read and outputs only content of the data file itself:
Therefore, JSON Path does not have FileName:
Any ideas how I can pass FileName from ZipFile Read to JSON Parser and then to JSON Splitter?
Thank you!
