Zip File Read – pass file name to text field
Hello, we have a data coming in a zip file. One of the requirements is to read file name and send it to a text field so it can be loaded in to one of the columns in Oracle table.
For example:
Fil...
Forum Discussion
Thank you, Diane. Unfortunetly, FileName is not coming through after Json Parser and therefore, there is no way to get to it in JSON Splitter.
ZipFile Read produces following output:
JSON Parser follows directly after ZipFile Read and outputs only content of the data file itself:
Therefore, JSON Path does not have FileName:
Any ideas how I can pass FileName from ZipFile Read to JSON Parser and then to JSON Splitter?
Thank you!
(As you found out, using BinaryToDocument is one approach, I’m just offering another for reference)
I can offer a solution that is possible if you’re on the new 4.16 release. Since the JSONParser doesn’t pass through the header from the binary document, you can use a child pipeline to do the parsing and pass the filename as a pipeline parameter that can be referenced anywhere in the child pipeline. This approach is possible in 4.16 since the PipelineExecute snap can now support binary views.
You can switch the type of view by going into the “Views” tab and changing the value under the “Type” column for the given view:
So, your pipeline will look something like the following with the binary documents from the zip file going into a child pipeline:
And, the $['content-location'] field containing the file name being passed as a parameter to the child execution in the PipelineExecute:
The child pipeline would then have the JSONParser and a Mapper to add in the $FileName field:
I’m attaching the parent and child pipelines as well:
ParseJsonWithFilename_2019_02_18.slp (4.5 KB)
ReadZipFileAndParse_2019_02_18.slp (3.7 KB)
