Hi,
I am writing a zip file and I have a document id that I want to use as the zip file name. Could you suggest how to achieve it?
Apologies, the datatype is local datetime. That’s why.
I believe .toString() will do the job
Hi @amit.saroha,
One approach is to put the snap that writes the file into another pipeline and use it as a child of the current one.
Inside child, you will create a parameter and you will use this parametes as name of the file.
With Pipeline Execute you will call that child pipeline.
Regards,
Viktor
Scenario above is for if you write a file. If you read you can simply toggle button for the Expression Builder and select the $DocumentID
Thanks, @viktor_n - I tried but it didn’t give the desired result. I guess something is missing. Please see the below screenshot.
On the left side there is a botton( = ) check that and replace file name with this one "Temp_Files/" + $DocumentId + ".zip"
