As we cannot mark multiple suggestions as “Solutions”, wanted to summarize the solution that will work for this use case:
1. $.entries().sort((a,b) => a[0].localeCompare(b[0])).reduce((acc,curr) => acc.extend({[curr[0]]:curr[1]}),{})
2. $.keys().sort().toObject((k,i)=> k, (k,i)=> $.get(k))
Both the expressions mentioned above will ONLY work if we are at the last stage of the hierarchy.
How I broke the hierarchy: Using JSON Splitter to reorganise JSON - #3 by Supratim
Thank you @AleksandarAngelevski , @alchemiz and @Supratim for your inputs. Closing this thread now.
$.keys().sort().reverse().toObject((k,i)=> k, (k,i)=> $.get(k))
Yup, this is for sorting in reverse alphabetical order. Thank you @alchemiz
