JSON Object Diff
Is there a way to easily show what key values do not match between two JSON objects? If I have two objects with the same keys, can I output just the keys and values that do not match between the two objects? I am looking for a way to do this without having to create an equality expression for each key.
How to use object filter method to filter dictionary list
What is the correct expression from the below used to filter the records that have the Status field set to Delete Sample Payload : [{ “data”: [ { “Name”: “Harsha”, “Id”: “1234”, “City”: “NY”, “Status”: “Delete” }, { “Name”: “Chaithanya”, “Id”: “1235”, “City”: “NY”, “Status”: “Active” } ] }] • $data.filter($data.Status!=‘Delete’) • $data.filter(x=>x[$Status]!=‘Delete’)’ • $data.filter(x=>x[data.Status]!=‘Delete’) • $data.filter(x=>x[“Status”]!=‘Delete’)
Swap keys and values
Hi, I have a use case of lookup function where I have to use the same expression library but the lookup will happen both on the basis of key and value pair. Below is the expression library that I have uploaded { “Lookup”: { “Key1”: “Value1”, “Key2”: “Value2”, “Key3”: “Value3”, “Key4”:“Value4” } } Now I will get value1 from previous snaps, I want to use value1 to retrieve data as Key1. Can you suggest how this can be achieved? Regards, Shreegeet
