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Sort field names alphabetically in JSON source data

darshthakkar
Valued Contributor

Hi Team,

I have my source data coming in JSON format. I want to sort the fields inside the JSON format alphabetically. One way is to use a mapper and arrange them one-one alphabetically but it is a tedious task if the fields are more. Can we use an expression in mapper or any other snap that does this for us?

Thank you.

Best Regards,
Darsh

2 ACCEPTED SOLUTIONS

Aleksandar_A
Contributor III

Hi @darshthakkar,

One approach will be to Map the input document with the following expression:

$.entries().sort((a,b) => a[0].localeCompare(b[0])).reduce((acc,curr) => acc.extend({[curr[0]]:curr[1]}),{})

Note: This will only sort properties on first level.

Let me know if this helps.

BR,
Aleksandar.

View solution in original post

darshthakkar
Valued Contributor

As we cannot mark multiple suggestions as “Solutions”, wanted to summarize the solution that will work for this use case:

1. $.entries().sort((a,b) => a[0].localeCompare(b[0])).reduce((acc,curr) => acc.extend({[curr[0]]:curr[1]}),{})

2. $.keys().sort().toObject((k,i)=> k, (k,i)=> $.get(k))

Both the expressions mentioned above will ONLY work if we are at the last stage of the hierarchy.

How I broke the hierarchy: Using JSON Splitter to reorganise JSON - #3 by Supratim

Thank you @AleksandarAngelevski , @alchemiz and @Supratim for your inputs. Closing this thread now.

View solution in original post

12 REPLIES 12

Well, if the data that we have on input is in different format I might consider another approach because this is a special use case.

Makes sense, thank you @AleksandarAngelevski.

Alternative expression

$.keys().sort().toObject((k,i)=> k, (k,i)=> $.get(k))

image

Thank you so much @alchemiz for your suggestion.
I’m sure it is going to work, will try and keep you posted…

darshthakkar
Valued Contributor

Hey @alchemiz,

The solution you provided worked, the only consideration is that - “You need to be at the bottom of the hierarchy for sorting to work”.

Thank you, anyways 🙂