ContributionsMost RecentMost LikesSolutionsRe: To replace more than one character in string by looking up another field value HI @parthiban.jks I will try to explain to you the best I can do $VARIABLE_ID.split(',').reduce((acc, cur, index) => acc.replaceAll([cur], $VARIABLE_VALUE.split(',')[index]), $TRANSLATION_ID) .reduce() is an array function which accepts 2 arguments, first is the callback function(arrow funciton) and the second is the initialValue, so to use the reduce you’ll need an array, so what I’m doing is taking the $VARIABLE_ID and spliting by comma, so this will return an array of strings divided at the supplied separator(comma “,”). The reducer walks through that array element-by-element,and at each step, using the currentValue of the array, finds that currentValue(‘A’, ‘B’, …) in $TRANSLATION_ID and repalce it with value present in VARIABLE_VALUE consequently, what I mean with this is that I’m also splitting the $VARIABLE_VALUE by comma, this will also return an array, so I can access the value, which needs to be replace in $TRANSLATION_ID, with the index of the first array consequently .reduce((accumulator, currentValue, currentIndex, arr) => , initialValue) { "PHRASE_SEQ": 630, "PHRASE_ID": "Store at °C to [Y]°C", "PLACEMENT": "13", "TRANSLATION_ID": "Store at [A]°C to [B]°C", "VARIABLE_ID": "A,B", "VARIABLE_VALUE": "2,8" } $VARIABLE_ID.split(',') --> ['A', 'B'] - array $VARIABLE_VALUE.split(',') --> ['2', '8'] - array $VARIABLE_ID.split(',').reduce((acc, cur, index) => acc.replaceAll([cur], $VARIABLE_VALUE.split(',')[index]), $TRANSLATION_ID) ['A', 'B'].reduce((acc, cur, index) => acc.replaceAll([cur], ['2', '8'][index]) , "Store at [A]°C to [B]°C" ) With this syntax ['2', '8'][index] when index is 0 we will get the value '2', in the next iteration the index will be increment by 1 so we will get the value '8' In the first step(first iteration) the currentValue(cur) is ‘A’ and the currentIndex (index) is 0, initialValue = $TRANSLATION_ID or “Store at [A]°C to [B]°C”, and accumulator = the result from previous calls or the initialValue(in the first iteration) also value that we end with. In the function we updating the accumulator with new value, so acc.replaceAll([cur], $VARIABLE_VALUE.split(',')[index]) in the first iteration accumulator(acc) = “Store at [A]°C to [B]°C”, and replaceAll method returns a new string with all matches of a currentValue [‘A’], replaced by a value form $VARIABLE_VALUE ‘2’. Because the index is 0 in the first iteration this syntax $VARIABLE_VALUE.split(',')[index] would give the value ‘2’ from $VARIABLE_VALUE(array). In the second interation the index will be 1, currentValue ‘B’ and accumulator will be updated withvalue from the previous call, that is “Store at 2°C to [B]°C”, and so on until the last element of the array is reached I hope this will helps you to understand better about reduce function, if not let me know I will try to explain better BR Kristijan Re: To replace more than one character in string by looking up another field value Hi @RaymanPrince You can try to use the expression below in a mapper $VARIABLE_ID != null && $VARIABLE_VALUE != null && $.extend({ 'TRANSLATION_ID': $VARIABLE_ID.split(',').reduce((acc, cur, index) => acc.replaceAll([cur], $VARIABLE_VALUE.split(',')[index]),$TRANSLATION_ID) }) || $ Re: How to filter json document based on keys present in another object Hi @Ajay_Chawda Try to use the following expression and let me know if this helps you $.entries().filter(item => $group.findIndex(x => x.name == item[0]) != -1 ).reduce((acc, cur) => acc.extend({[cur[0]]: cur[1]}),{}) BR Kristijan